Solid ammonium carbamate dissociated into N-H-3- and C-O-2- as - N-H-4-COON-H-2-left-sright- rightleftharpoons 2N-H-3-left-gright- - C-O-2-left-gright- The total pressure equilibrium is 0-225 atm- -K-p- is Xtimes -10-3- -atm-3- 1000X is-

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Toppr Admin · Accepted Answer

Total pressure -2P-P-3P-0-225atmP-0-075atm2P-0-15atmKP-P2NH3PCO2-0-150-15atm-2-xD7-0-0750-15atmKP-1-687-xD7-10-x2212-3atm3-X-xD7-10-x2212-3atm3X-1-6871000X-1687

Solid ammonium carbamate dissociated into $N H_{3}$ and $C O_{2}$ as : $N H_{4} C O O N H_{2} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g)$ . The total pressure at equilibrium is 0.225 atm. $K_{p}$ is $X \times 10^{- 3} {a t m}^{3}$ . $1000 X$ is__________.

Total pressure $= 2 P + P = 3 P = 0.225 a t m$
$P = 0.075 a t m$
$2 P = 0.15 a t m$
$K_{P} = P_{N H_{3}}^{2} P_{C O_{2}} = (0.150.15 a t m)^{2} \times 0.0750.15 a t m$
$K_{P} = 1.687 \times 10^{- 3} a t m^{3} = X \times 10^{- 3} a t m^{3}$
$X = 1.687$
$1000 X = 1687$

Solid ammonium carbamate dissociated into NH3 and CO2 as : NH4COONH2(s)⇌2NH3(g)+CO2(g). The total pressure at equilibrium is 0.225 atm. Kp is X×10−3atm3. 1000X is__________.

Total pressure =2P+P=3P=0.225atmP=0.075atm2P=0.15atmKP=P2NH3PCO2=(0.150.15atm)2×0.0750.15atmKP=1.687×10−3atm3=X×10−3atm3X=1.6871000X=1687

Solid ammonium carbamate dissociated into $N H_{3}$ and $C O_{2}$ as : $N H_{4} C O O N H_{2} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g)$ . The total pressure at equilibrium is 0.225 atm. $K_{p}$ is $X \times 10^{- 3} {a t m}^{3}$ . $1000 X$ is__________.

Total pressure $= 2 P + P = 3 P = 0.225 a t m$
$P = 0.075 a t m$
$2 P = 0.15 a t m$
$K_{P} = P_{N H_{3}}^{2} P_{C O_{2}} = (0.150.15 a t m)^{2} \times 0.0750.15 a t m$
$K_{P} = 1.687 \times 10^{- 3} a t m^{3} = X \times 10^{- 3} a t m^{3}$
$X = 1.687$
$1000 X = 1687$