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Question

Solve $\frac{x}{3} + \frac{y}{5} = 1, 7 x - 15 y = 21$

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Solution

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$\frac{x}{3} + \frac{y}{5} = 1$
$5 x + 3 y = 15 \to 1$
$7 x - 15 y = 21 \to 2$
Multiplying $1$ by $5$ we get
$25 x + 15 y = 75$
$7 x - 15 y = 21$
$32 x = 96$
$x = 3$
$7 (3) - 15 y = 21$
$15 y = 0$
$y = 0$
$∴ x = 3; y = 0$

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