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Standard X
Mathematics
Question
Solve for x:
1
a
+
b
+
x
=
1
a
+
1
b
+
1
x
;
(
x
≠
0
)
Open in App
Solution
Verified by Toppr
Consider
1
a
+
b
+
x
=
1
a
+
1
b
+
1
x
⇒
1
a
+
b
+
x
−
1
x
=
1
a
+
1
b
⇒
x
−
a
−
b
−
x
x
(
a
+
b
+
x
)
=
a
+
b
a
b
⇒
−
a
−
b
a
x
+
b
x
+
x
2
=
a
+
b
a
b
⇒
−
(
a
+
b
)
a
b
=
(
a
+
b
)
(
x
2
+
a
x
+
b
x
)
⇒
−
a
b
=
x
2
+
a
x
+
b
x
⇒
x
2
+
a
x
+
b
x
+
a
b
=
0
⇒
x
(
x
+
a
)
+
b
(
x
+
a
)
=
0
⇒
(
x
+
a
)
(
x
+
b
)
=
0
⇒
x
=
−
a
o
r
−
b
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Q1
Solve for x:
1
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+
b
+
x
=
1
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1
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;
(
x
≠
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Q2
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Q3
Solve for
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+
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=
1
a
+
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+
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;
where
a
≠
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,
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≠
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,
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≠
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Q4
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