Solve n - 5 - 19-n-1-

Question

Toppr Admin · Accepted Answer

Given- n-5-19-n-x2212-1-x21D2-n-5-19n-x2212-19Lets-xA0- separate the variables and constants by using the transpose rules-x21D2-19n-x2212-n-5-19-x21D2-18n-24-x21D2-n-2418-xA0-x21D2-n-43

Solve: $n + 5 = 19 (n - 1)$

Given: $n + 5 = 19 (n - 1)$
$\Rightarrow n + 5 = 19 n - 19$
Lets separate the variables and constants by using the transpose rules
$\Rightarrow 19 n - n = 5 + 19$
$\Rightarrow 18 n = 24$
$\Rightarrow n = \frac{24}{18}$
$\Rightarrow n = \frac{4}{3}$

Solve: n+5=19(n−1)

Given: n+5=19(n−1)⇒n+5=19n−19Lets separate the variables and constants by using the transpose rules⇒19n−n=5+19⇒18n=24⇒n=2418 ⇒n=43

Solve: $n + 5 = 19 (n - 1)$

Given: $n + 5 = 19 (n - 1)$
$\Rightarrow n + 5 = 19 n - 19$
Lets separate the variables and constants by using the transpose rules
$\Rightarrow 19 n - n = 5 + 19$
$\Rightarrow 18 n = 24$
$\Rightarrow n = \frac{24}{18}$
$\Rightarrow n = \frac{4}{3}$