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Question

Solve the differential equation (xy2)dx+2xydy=0.
  1. y2+xlnax=0
  2. y2ylnax=0
  3. y2xlnax=0
  4. y2+ylnax=0

A
y2xlnax=0
B
y2+xlnax=0
C
y2ylnax=0
D
y2+ylnax=0
Solution
Verified by Toppr

(xy2)dx+2xydy=02ydydxy2x=1
Substitute v=y2dv=2ydy
dvdxvx=1 ...(1)
Here P=1xPdx=1xdx=logx=log1x
I.F.=elog1x=1x
Multiplying (1) by I.F. we get
1xdvdxvx2=1x
Integrating both sides w.r.t x we get
vx=1xdx+a=logx+ay2=xlogax

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