(x−y2)dx+2xydy=0⇒2ydydx−y2x=−1 Substitute v=y2⇒dv=2ydy dvdx−vx=−1 ...(1) Here P=−1x⇒∫Pdx=−∫1xdx=−logx=log1x ∴I.F.=elog1x=1x Multiplying (1) by I.F. we get 1xdvdx−vx2=−1x Integrating both sides w.r.t x we get vx=−∫1xdx+a=−logx+a⇒y2=xlogax
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