The given quadratic equation is x2+3=0
On comparing the given equation with ax2+bx+c=0,
we get a=1,b=0, and c=3
Therefore, the discriminant of the given equation is
D=b2−4ac=02−4×1×3=−12
Therefore, the required solutions are
−b±√D2a=±√−122×1=±√12i2
=±2√3i2=±√3i