Question

Solve the equation $x^2+3x+9=0$

Answer 1

The given quadratic equation is $x^2+3x+9=0$
On comparing the given equation with $a{x}^2+bx+c=0$, we obtain
$a=1,b=3,$ and $c=9$
Therefore, the discriminant of the given equation is
$D=b^2-4ac=3^2-4\times 1\times 9=9-36=-27$
Therefore, the required solutions are
$\frac{-b\pm \sqrt{D}}{2a}=\frac{-3\pm \sqrt{-27}}{2\left(1\right)}=\frac{-3\pm 3\sqrt{-3}}{2}=\frac{-3\pm 3\sqrt{3}i}{2}$