The given quadratic equation is 2x2+x+1=0
On comparing the given equation with ax2+bx+c=0,
we obtain a=2,b=1 and c=1
Therefore, the discriminant of the given equation is
D=b2−4ac=12−4×2×1=1−8=−7
Therefore, the required solutions are
−b±√D2a=−1±√−72×2=−1±√7i4