Solve the equation x2−x+2=0
The given quadratic equation is x2−x+2=0
On comparing the given equation with ax2+bx+c=0,
we obtain a=1,b=−1, and c=2
Therefore, the discriminant of the given equation is
D=b2−4ac
=(−1)2−4×1×2
=1−8
=−7
Therefore, the required solutions are
−b±√D2a
=−(−1)±√−72×1
=1±√7i2