The given quadratic equation is √2x2+x+√2=0
On comparing the given equation with ax2+bx+c=0,
we obtain a=√2,b=1, and c=√2
Therefore, the discriminant of the given equation is
D=b2−4ac=12−4×√2×√2=1−8=−7
Therefore, the required solutions are
−b±√D2a=−(1)±√−72×√2=−1±√7i2√2