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Question

Solve the equation:-
limxπ/2 tan 2xxπ/2

Solution
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limxπ2tan2xxπ2

LHL=limh0tan2(π2h)π2hπ2

=limh0tan(π2h)h

=limh0tan2hh

=limh02tan2h2h=2

RHL=limh0+tan2(π2+h)π2+hπ2

=limh0+tan(π+2h)h

=limh0+tan2hh

=limh0+2tan2h2h=2

Thus,limxπ2tan2xxπ2=2

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