Question

Solve the following equation:
$\frac{3y+4}{2-6y}=\frac{-2}{5}$

Answer 1

Given equation is $\frac{3y+4}{2-6y}=\frac{-2}{5}$

On multiplying both sides by $5(2-6y)$, we get:

$5(3y+4)=-2(2-6y)$

$\Rightarrow 15y+20$ $=-4+12y$

Transposing $12y$ to LHS and $20$ to RHS, we get:

$15y-12y=-4-20$

$\Rightarrow 3y=-24$

$\Rightarrow y=-8$

Hence, $y=-8$ is the solution of the given equation.