Solve the following -In Delta PQR - - NM - RQ- If PM - 15- MQ - 10- NR - 8- then PN-

Question

Toppr Admin · Accepted Answer

Given - NM - RQ- and -PM - 15- MQ - 10- NR - 8-since-160- NM - RQ- then by basic proportionality theorem-dfrac -PN-NR-dfrac -PM-MQ-dfrac -PN-8-dfrac -15-10-PN-dfrac -15-10-times 8-PN-dfrac 32 -times 8-therefore- PN-12-

Solve the following :
In $$\Delta PQR , \, NM || RQ$$. If $$PM = 15, MQ = 10, NR = 8$$, then find $$PN$$.

Given $$\, NM || RQ$$ and $$PM = 15, MQ = 10, NR = 8$$

since $$\, NM || RQ$$ then by basic proportionality theorem

$$\dfrac {PN}{NR}=\dfrac {PM}{MQ}$$

$$\dfrac {PN}{8}=\dfrac {15}{10}$$

$$PN=\dfrac {15}{10}\times 8$$

$$PN=\dfrac 32 \times 8$$

$$\therefore\ PN=12$$

Solve the following :In $$\Delta PQR , \, NM || RQ$$. If $$PM = 15, MQ = 10, NR = 8$$, then find $$PN$$.

Given $$\, NM || RQ$$ and $$PM = 15, MQ = 10, NR = 8$$since $$\, NM || RQ$$ then by basic proportionality theorem$$\dfrac {PN}{NR}=\dfrac {PM}{MQ}$$$$\dfrac {PN}{8}=\dfrac {15}{10}$$$$PN=\dfrac {15}{10}\times 8$$$$PN=\dfrac 32 \times 8$$$$\therefore\ PN=12$$

Solve the following :
In $$\Delta PQR , \, NM || RQ$$. If $$PM = 15, MQ = 10, NR = 8$$, then find $$PN$$.

Given $$\, NM || RQ$$ and $$PM = 15, MQ = 10, NR = 8$$

since $$\, NM || RQ$$ then by basic proportionality theorem

$$\dfrac {PN}{NR}=\dfrac {PM}{MQ}$$

$$\dfrac {PN}{8}=\dfrac {15}{10}$$

$$PN=\dfrac {15}{10}\times 8$$

$$PN=\dfrac 32 \times 8$$

$$\therefore\ PN=12$$