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Question

Solve the following inequalities graphically in two-dimensional plane:
3x+2y6

Solution
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3x+2y6
Lets first draw graph of
x 0 2
y 3 0

3x+2y=6

Putting x=0 in (1)
3(0)+2y=6
0+2y=6
2y=6
y=62
y=3

Putting y=0 in (1)
3x+2(0)=6
3x+0=6
3x=6
x=63
x=2

Drawing graph
x 0 2
y 3 0

Point to be plotted are (0,3),(2,0)

Checking for (0,0)
Putting x=0,y=0
3x+2y6
3(0)+2(0)6
06

Which is true
Hence origin lies in the plane 3x+2y6.
So, we shade left side of line.


1521818_419403_ans_e4b23168005442468e7abd47ce608143.png

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