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Standard XI
Mathematics
NCERT
Question
Solve the following inequalities graphically in two-dimensional plane:
−
3
x
+
2
y
≥
−
6
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Solution
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−
3
x
+
2
y
≥
−
6
Lets first draw graph of
x
0
2
y
−
3
0
−
3
x
+
2
y
=
−
6
Putting
x
=
0
in (1)
−
3
(
0
)
+
2
y
=
−
6
0
+
2
y
=
−
6
2
y
=
−
6
y
=
−
6
2
y
=
−
3
Putting
y
=
0
in (1)
−
3
x
+
2
(
0
)
=
−
6
−
3
x
+
0
=
−
6
−
3
x
=
−
6
x
=
−
6
−
3
x
=
2
Drawing graph
x
0
2
y
−
3
0
Point to be plotted are
(
0
,
−
3
)
,
(
2
,
0
)
Checking for
(
0
,
0
)
Putting
x
=
0
,
y
=
0
−
3
x
+
2
y
≥
−
6
−
3
(
0
)
+
2
(
0
)
≥
−
6
0
≥
−
6
Which is true
Hence origin lies in the plane
−
3
x
+
2
y
≥
−
6
.
So, we shade left side of line.
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Similar Questions
Q1
Solve the following inequalities graphically in two-dimensional plane:
−
3
x
+
2
y
≥
−
6
View Solution
Q2
Solve the given inequality graphically in two-dimensional plane: –
3
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+ 2
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