Solve the following inequalities graphically in two-dimensional plane:
$x + y < 5$

Question

Solve the following inequalities graphically in two-dimensional plane-x -y -leq- 2

Toppr Admin · Accepted Answer

X-x2212-y-x2264-2 -xA0-is the shaded region shown in the graph-If we put O-0-0- in the LHS-we get LHS-0Now LHS-lt-0-xA0-Means O-0-0- lies on -quot-less than -quot- side of -xA0-the line-Hence required region is -quot-origin-quot- side of the-xA0-line-

Solve the following inequalities graphically in two-dimensional plane:
$x - y \leq 2$

$x - y \leq 2$ is the shaded region shown in the graph.
If we put $O (0, 0)$ in the LHS,we get LHS $= 0$
Now $L H S < 0$
Means $O (0, 0)$ lies on "less than " side of the line.
Hence required region is "origin" side of the line.

Solve the following inequalities graphically in two-dimensional plane:x−y≤2

x−y≤2 is the shaded region shown in the graph.If we put O(0,0) in the LHS,we get LHS=0Now LHS<0 Means O(0,0) lies on "less than " side of the line.Hence required region is "origin" side of the line.

Solve the following inequalities graphically in two-dimensional plane:
$x - y \leq 2$

$x - y \leq 2$ is the shaded region shown in the graph.
If we put $O (0, 0)$ in the LHS,we get LHS $= 0$
Now $L H S < 0$
Means $O (0, 0)$ lies on "less than " side of the line.
Hence required region is "origin" side of the line.