Question

Solve the following inequation :
$$ \dfrac{2y + 1}{3} + 1 \leq 3 , y\, \varepsilon \, W $$

Answer 1

Given:

$$ \dfrac{2y + 1}{3} + 1 \leq 3 $$

$$ \dfrac{2y + 1 + 3}{3} \leq 3 $$

$$ \dfrac{2y + 4}{3} \leq 3 $$

$$ (2y + 4) \leq 3 \times 3 $$

$$ 2y + 4 \leq 9 $$

$$ 2y \leq 9 - 4 $$

$$ 2y \leq 5 $$

We get ,

$$ y \leq \dfrac{5}{2} $$

As $$ y\, \varepsilon \, W $$ ,

Therefore , solution set $$ = \left \{0 , 1 , 2 \right \} $$