Solve the given inequalities graphically-x - y -leq- 6- x - y -geq- 4

Question

Toppr Admin · Accepted Answer

Blue line is x-y-6 and red line is x-y-4Now we have to look the region which is below or on the x-y-6 line and above or on the x-y-4 line-So required region is in between the two lines-

Solve the given inequalities graphically:
$x + y$ $\leq$ $6, x + y$ $\geq$ $4$

Blue line is $x + y = 6$ and red line is $x + y = 4$
Now we have to look the region which is below or on the $x + y = 6$ line and above or on the $x + y = 4$ line.
So required region is in between the two lines.

Solve the given inequalities graphically:x+y≤ 6,x+y ≥ 4

Blue line is x+y=6 and red line is x+y=4Now we have to look the region which is below or on the x+y=6 line and above or on the x+y=4 line.So required region is in between the two lines.

Solve the given inequalities graphically:
$x + y$ $\leq$ $6, x + y$ $\geq$ $4$

Blue line is $x + y = 6$ and red line is $x + y = 4$
Now we have to look the region which is below or on the $x + y = 6$ line and above or on the $x + y = 4$ line.
So required region is in between the two lines.