Solve4dfrac -2-3- - 3dfrac -1-4-

Question

Toppr Admin · Accepted Answer

-4-dfrac -2-3- - 3-dfrac -1-4- -dfrac -3-times 4- - 1-3- - -dfrac -3-times 4- - 1-4- -dfrac -14-3- - -dfrac -13-4- -dfrac -14-times 4- - -13-times 3-12- - -dfrac -56 - 39-12- - -dfrac -95-12-

Solve
$$4\dfrac {2}{3} + 3\dfrac {1}{4}$$

$$4\dfrac {2}{3} + 3\dfrac {1}{4}$$
$$= \dfrac {(3\times 4) + 1}{3} + \dfrac {(3\times 4) + 1}{4}$$
$$= \dfrac {14}{3} + \dfrac {13}{4}$$
$$= \dfrac {(14\times 4) + (13\times 3)}{12} = \dfrac {56 + 39}{12} = \dfrac {95}{12}$$.

Solve$$4\dfrac {2}{3} + 3\dfrac {1}{4}$$

$$4\dfrac {2}{3} + 3\dfrac {1}{4}$$$$= \dfrac {(3\times 4) + 1}{3} + \dfrac {(3\times 4) + 1}{4}$$$$= \dfrac {14}{3} + \dfrac {13}{4}$$$$= \dfrac {(14\times 4) + (13\times 3)}{12} = \dfrac {56 + 39}{12} = \dfrac {95}{12}$$.

Solve
$$4\dfrac {2}{3} + 3\dfrac {1}{4}$$

$$4\dfrac {2}{3} + 3\dfrac {1}{4}$$
$$= \dfrac {(3\times 4) + 1}{3} + \dfrac {(3\times 4) + 1}{4}$$
$$= \dfrac {14}{3} + \dfrac {13}{4}$$
$$= \dfrac {(14\times 4) + (13\times 3)}{12} = \dfrac {56 + 39}{12} = \dfrac {95}{12}$$.