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Question

Solve
$$\dfrac {1}{2} + \dfrac {1}{3} + \dfrac {1}{6}$$

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Solution

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$$\dfrac {1}{2} + \dfrac {1}{3} + \dfrac {1}{6}$$
$$= \dfrac {(1\times 3) + (1\times 2) + (1\times 1)}{6}$$
$$= \dfrac {3 + 2 + 1}{6} = \dfrac {6}{6} = 1$$.

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