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Question

Solve
$$\dfrac {2}{3} + \dfrac {3}{4} + \dfrac {1}{2}$$

Solution
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$$\dfrac {2}{3} + \dfrac {3}{4} + \dfrac {1}{2}$$
$$= \dfrac {(2\times 4) + (3\times 3) + (1\times 6)}{12}$$
$$= \dfrac {8 + 9 + 6}{12} = \dfrac {23}{12}$$

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