Solve displaystyle frac-2x- - 5-10- - frac-x-5- - frac-x-1- - x- 1- 347

Question

Toppr Admin · Accepted Answer

2x-510-x5-x2212-x1-x2212-x2x-510-x-1-x2212-x-x2212-5x5-1-x2212-x-1-x2212-x-2x-5-2-x-1-x2212-x-x2212-5x-2x-x2212-2x2-5-x2212-5x-2-x-x2212-x2-x2212-5x-2x-x2212-2x2-5-x2212-5x-2x-x2212-2x2-x2212-10x-5-x2212-5xx-x2212-1

Solve $\frac{2 x + 5}{10} = \frac{x}{5} - \frac{x}{1 - x}$
$- 1$
$- 3$
$4$
$7$

$\frac{2 x + 5}{10} = \frac{x}{5} - \frac{x}{1 - x} \frac{2 x + 5}{10} = \frac{x (1 - x) - 5 x}{5 (1 - x)} (1 - x) (2 x + 5) = 2 (x (1 - x) - 5 x) 2 x - 2 x^{2} + 5 - 5 x = 2 (x - x^{2} - 5 x) 2 x - 2 x^{2} + 5 - 5 x = 2 x - 2 x^{2} - 10 x + 5 = - 5 x x = - 1$

Solve 2x+510=x5−x1−x−1−347

2x+510=x5−x1−x2x+510=x(1−x)−5x5(1−x)(1−x)(2x+5)=2(x(1−x)−5x)2x−2x2+5−5x=2(x−x2−5x)2x−2x2+5−5x=2x−2x2−10x+5=−5xx=−1

Solve $\frac{2 x + 5}{10} = \frac{x}{5} - \frac{x}{1 - x}$
$- 1$
$- 3$
$4$
$7$

$\frac{2 x + 5}{10} = \frac{x}{5} - \frac{x}{1 - x} \frac{2 x + 5}{10} = \frac{x (1 - x) - 5 x}{5 (1 - x)} (1 - x) (2 x + 5) = 2 (x (1 - x) - 5 x) 2 x - 2 x^{2} + 5 - 5 x = 2 (x - x^{2} - 5 x) 2 x - 2 x^{2} + 5 - 5 x = 2 x - 2 x^{2} - 10 x + 5 = - 5 x x = - 1$