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Standard XII
Mathematics
Question
Solve
n
+
3
1
3
−
n
+
2
1
2
=
n
−
4
1
10
. Then the value of
n
is obtained as
4
5
−
5
6
A
5
B
6
C
−
5
D
4
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Solution
Verified by Toppr
n
+
3
1
3
−
n
+
2
1
2
=
n
−
4
1
10
(
n
+
3
)
×
3
−
(
n
+
2
)
×
2
=
(
n
−
4
)
×
10
3
n
+
9
−
2
n
−
4
=
10
n
−
40
9
n
=
45
n
=
5
So correct answer will be option B
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Similar Questions
Q1
Solve
n
+
3
1
3
−
n
+
2
1
2
=
n
−
4
1
10
. Then the value of
n
is obtained as
View Solution
Q2
Solve :
n
4
−
5
=
n
6
+
1
2
View Solution
Q3
If
n
is a positive integer, then find the value of
⎡
⎢
⎣
n
+
2
C
n
n
+
3
C
n
+
1
n
+
4
C
n
+
2
n
+
3
C
n
+
1
n
+
4
C
n
+
2
n
+
5
C
n
+
3
n
+
4
C
n
+
2
n
+
5
C
n
+
3
n
+
6
C
n
+
4
⎤
⎥
⎦
.
View Solution
Q4
If
lim
n
→
∞
(
3
1
⋅
2
⋅
4
+
4
2
⋅
3
⋅
5
+
5
3
⋅
4
⋅
6
+
⋯
+
n
+
2
n
(
n
+
1
)
(
n
+
3
)
)
can be expressed as rational in the lowest form
m
n
where
m
,
n
∈
N
,
then the value of
(
m
+
n
)
is
View Solution
Q5
The value of
lim
n
→
∞
1
+
2
4
+
3
4
+
.
.
.
+
n
4
n
5
−
lim
n
→
∞
1
+
2
3
+
3
3
+
.
.
.
+
n
3
n
5
is
View Solution