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Question

Solve: $(x + 2)^{3} = 2 x (x^{2} - 1)$

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Solution

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$(x + 2)^{3} = 2 x (x^{2} - 1)$
$∴ (a + b)^{3} = a^{3} + b^{3} + 3 a^{2} b + 3 a b^{2}$
$x^{3} + 8 + 3 \times x^{2} \times 2 + 3 \times x \times 2^{2} = 2 x^{3} - 2 x$
$x^{3} + 8 + 6 x^{2} + 3 \times 4 \times x = 2 x^{3} - 2 x$
$x^{3} + 8 + 6 x^{2} + 12 x - 2 x^{3} + 2 x = 0$
$- x^{3} + 6 x^{2} + 14 x + 8 = 0$

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Similar Questions

Q1

Solve:

(x + 2)^{3} = 2 x (x^{2} - 1)

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Q2

$(x + 2)^{3} + (x - 2)^{3} = 2 x (x^{2} + 12)$

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Q3

Check whether the following is quadratic equation.

(x + 2)^{3} = 2 x (x^{2} - 1)

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Q4

Check whether the following are Quadratic equations

{(x + 2)}^{3} = 2 x (x^{2} - 1)

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Q5

Simplify

(x + 2)^{3} = 2 x (x^{2} - 1)

and check whether its is a quadratic equation.

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