Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Special Examples of Oxidation Number Determination 1. Oxidation number of sulphur in peroxo mono sulphuric acid (H2SOs) Let us draw its structure H-O-5-0-0-H Here we have to consider oxidation number of H = +1 Oxidation number of oxygen in peroxy linkage = -1 Oxidation number of oxygen in oxide form = -2 Here two oxygen atoms are in form of peroxide and three oxygen atoms are in form of oxide 2+1) + x + 3(-2) + 2(-1) = 0 = x= + 6

Open in App
Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
Which of the following statements regarding H2SO5 is/are incorrect?
View Solution
Q2
In H2O2, both oxygen atoms have same oxidation number but in Na2S2O3, the two S-atoms do not have same oxidation number.
If true enter 1, else enter 0.
View Solution
Q3
Assertion :Oxidation number of sulphur in H2SO5 is +6. Reason: It has one peroxy linkage.
View Solution
Q4
The binary compounds of oxygen with other elements are called oxides. They are classified either depending upon their acid-base characteristics or on the basis of oxygen content.
(a) Normal oxides: These oxides which contain oxygen atoms as permitted by the normal oxidation number, i.e. $$-2$$ Normal oxide may be acidic, basic, amphoteric or neutral.
(b)Polyoxides: The oxides which contain oxygen atoms different than those permitted by the normal oxidation number of $$-2$$
(i) Peroxides: Two oxygen atoms are linked to each other and each oxygen has $$-1$$ oxidation number. They contain $$(O-O)^{2-}$$ unit.
(ii) Superoxides: These oxides contain $$(O-O)^{-1}$$ unit,
i.e. each $$O$$- atom has oxidation number $$-1/2$$
(c) Suboxides: These contain low content of oxygen than expected.
(d) Mixed oxides: These oxides are made of two simpler oxides.

Which of the following pairs contains neutral oxides?
View Solution
Q5
Reason
The oxygen of peroxide is in -1 oxidation state and it is converted to zero
oxidation state in $$ \mathrm{O}_{2} $$ and -2 oxidation state in $$ \mathrm{H}_{2} \mathrm{O} $$.
Assertion
The decomposition of hydrogen peroxide to form water and oxygen is
an example of a disproportionation reaction.
View Solution