Speed of sound in air is 350 ms-1- fundamental frequency of an organ pipe of 50 cm length will be175 Hz350 Hz700 Hz500 Hz

Question

Toppr Admin · Accepted Answer

Fundamental frequency of an open organ pipe is given by -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- n1-v-x3BB-v-2l -where v-speed of sound in air -350m-s-given-xA0- -xA0- -xA0- -xA0- -xA0- -xA0-x3BB- wavelength -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-l- length of organ pipe -50cm-0-50m -xA0- given- -therefore - -xA0-n1-350-2-xD7-0-50-350Hz

Speed of sound in air is 350 $m s^{- 1}$ , fundamental frequency of an open organ pipe of 50 cm length will be
175 Hz
350 Hz
700 Hz
500 Hz

Fundamental frequency of an open organ pipe is given by ,
$n_{1} = v / λ = v / 2 l$ ,
where $v =$ speed of sound in air ( $= 350 m / s, g i v e n$ ),
$λ =$ wavelength ,
$l =$ length of organ pipe ( $= 50 c m = 0.50 m$ , given) ,
therefore , $n_{1} = 350 / (2 \times 0.50) = 350 H z$

Speed of sound in air is 350 ms−1, fundamental frequency of an open organ pipe of 50 cm length will be175 Hz350 Hz700 Hz500 Hz

Fundamental frequency of an open organ pipe is given by , n1=v/λ=v/2l ,where v=speed of sound in air (=350m/s,given), λ= wavelength , l= length of organ pipe (=50cm=0.50m , given) ,therefore , n1=350/(2×0.50)=350Hz

Speed of sound in air is 350 $m s^{- 1}$ , fundamental frequency of an open organ pipe of 50 cm length will be
175 Hz
350 Hz
700 Hz
500 Hz

Fundamental frequency of an open organ pipe is given by ,
$n_{1} = v / λ = v / 2 l$ ,
where $v =$ speed of sound in air ( $= 350 m / s, g i v e n$ ),
$λ =$ wavelength ,
$l =$ length of organ pipe ( $= 50 c m = 0.50 m$ , given) ,
therefore , $n_{1} = 350 / (2 \times 0.50) = 350 H z$