State the number of images of an object placed between two mirrors, formed in each case when mirrors are inclined to each other at $(a) 90^{\circ}$ and $(b) 60^{\circ}$ .

Question

State the number of images of an object placed between two mirrors- formed in each when mirrors are inclined to each other -a- 90-circ- and -b- 60-circ-a- 4- -b- 6-a- 3- -b- 5-a- 2- -b- 3-a- 1- -b- 2

Toppr Admin · Accepted Answer

-a- When -x3B8-900-n-36090-x2212-1-3-b- When -x3B8-600n-36060-x2212-1-5

State the number of images of an object placed between two mirrors, formed in each case when mirrors are inclined to each other at $(a) 90^{\circ}$ and $(b) 60^{\circ}$ .
$(a) 4$ , $(b) 6$
$(a) 3$ , $(b) 5$
$(a) 2$ , $(b) 3$
$(a) 1$ , $(b) 2$

(a) When $θ = 90^{0}$ ,
$n = \frac{360}{90} - 1 = 3$

(b) When $θ = 60^{0}$
$n = \frac{360}{60} - 1 = 5$

State the number of images of an object placed between two mirrors, formed in each case when mirrors are inclined to each other at (a)90∘ and (b)60∘.(a)4, (b)6(a)3, (b)5(a)2, (b)3(a)1, (b)2

(a) When θ=900,n=36090−1=3(b) When θ=600n=36060−1=5

State the number of images of an object placed between two mirrors, formed in each case when mirrors are inclined to each other at $(a) 90^{\circ}$ and $(b) 60^{\circ}$ .
$(a) 4$ , $(b) 6$
$(a) 3$ , $(b) 5$
$(a) 2$ , $(b) 3$
$(a) 1$ , $(b) 2$

(a) When $θ = 90^{0}$ ,
$n = \frac{360}{90} - 1 = 3$

(b) When $θ = 60^{0}$
$n = \frac{360}{60} - 1 = 5$