The pair of irrational numbers gives difference which is irrational are 2+2√3 and 3−3√2
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Solution
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To get the difference as irrational, the numbers need to have an irrational part which should be different from each other. The given pair of numbers are 2+2√3 and 3−3√2
On subtracting we get,
2+2√3−(3−3√2)=−1+2√3+3√2
It is an irrational number.
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