Steam undergoes decomposition high temperature as per the reactionH-2-O-g- rightleftharpoons H-2-g-frac-1-2-O-2-g- Delta H-circ-200 kJ mol-1- Delta S-circ-40 J mol-1-The temperature which equilibrium constant is unit is -3000 Kelvin5000 Kelvin5333 Kelvin5 Kelvin

Question

Toppr Admin · Accepted Answer

-x394-G-x2218-x394-H-x2218-x2212-T-x394-S-x2218-x2212-RTlnKeq-0-Keq-1-x21D2-T-x394-H-x2218-x394-S-x2218-200-xD7-10340-5000K

Steam undergoes decomposition at high temperature as per the reaction
$H_{2} O (g) ⇌ H_{2} (g) + \frac{1}{2} O_{2} (g), Δ H^{\circ} = 200 k J m o l^{- 1} Δ S^{\circ} = 40 J m o l^{- 1}$
The temperature at which equilibrium constant is unit is :
3000 Kelvin
5000 Kelvin
5333 Kelvin
5 Kelvin

$Δ G^{\circ} = Δ H^{\circ} - T Δ S^{\circ} = - R T l n K e q = 0 [K e q = 1]$ .
$\Rightarrow T = \frac{Δ H^{\circ}}{Δ S^{\circ}} = \frac{200 \times 10^{3}}{40} = 5000 K$

Steam undergoes decomposition at high temperature as per the reactionH2O(g)⇌H2(g)+12O2(g),ΔH∘=200kJmol−1ΔS∘=40Jmol−1The temperature at which equilibrium constant is unit is :3000 Kelvin5000 Kelvin5333 Kelvin5 Kelvin

ΔG∘=ΔH∘−TΔS∘=−RTlnKeq=0[Keq=1].⇒T=ΔH∘ΔS∘=200×10340=5000K

Steam undergoes decomposition at high temperature as per the reaction
$H_{2} O (g) ⇌ H_{2} (g) + \frac{1}{2} O_{2} (g), Δ H^{\circ} = 200 k J m o l^{- 1} Δ S^{\circ} = 40 J m o l^{- 1}$
The temperature at which equilibrium constant is unit is :
3000 Kelvin
5000 Kelvin
5333 Kelvin
5 Kelvin

$Δ G^{\circ} = Δ H^{\circ} - T Δ S^{\circ} = - R T l n K e q = 0 [K e q = 1]$ .
$\Rightarrow T = \frac{Δ H^{\circ}}{Δ S^{\circ}} = \frac{200 \times 10^{3}}{40} = 5000 K$