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Question

Subtract the second polynomial from the first.
$$2ab^{2} + 3a^{2}b - 4ab, \\ 3ab - 8ab^{2} + 2a^{2}b$$

Solution
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To find: = $$(2ab^{2} + 3a^{2}b - 4ab) - (3ab - 8ab^{2} + 2a^{2}b)$$
$$=2ab^{2} + 3a^{2} b - 4ab - 3ab + 8 ab^{2} - 2a^{2}b$$
$$=2ab^{2} + 8ab^{2} + 3a^{2}b - 2a^{2} b - 4ab - 3ab $$
$$=10ab^{2} + a^{2}b - 7ab$$

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