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Question

Subtract:
$$6a+3$$ form $$a^3-3a^2+4a+1$$

Solution
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$$\dfrac {a^3-3a^2 +4a+1\\ \quad \quad \quad \ \ \ +6a+3\\ \quad \quad \quad \ \ \ \ -\quad -}{\underline{a^3-3a^2 -2a-2}}$$

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