Sulphur trioxide is dissolved in heavy water to form a compound $X$ . The state of hybridisation of sulphur in $X$ is:

Question

Sulphur trioxide is dissolved in heavy water to form a compound X- The state of hybridisation of sulphur in X is-sp-3-dsp-2-sp-2-sp

Toppr Admin · Accepted Answer

Hybridisation is given by the following-xA0-formula-xA0-H-V-X-x2212-C-A2-xA0-Here- V- number of valence electrons in central atom-xA0-X- number of monovalent atoms around the central atom-xA0-C- positive charge on cation and-xA0-A- negative charge on anion-xA0-

Sulphur trioxide is dissolved in heavy water to form a compound $X$ . The state of hybridisation of sulphur in $X$ is:
$s p^{3}$
$d s p^{2}$
$s p^{2}$
$s p$

Hybridisation is given by the following formula:
$H = \frac{V + X - C + A}{2}$

Here, $V =$ number of valence electrons in central atom, $X =$ number of monovalent atoms around the central atom, $C =$ positive charge on cation and $A =$ negative charge on anion.

Sulphur trioxide is dissolved in heavy water to form a compound X. The state of hybridisation of sulphur in X is:sp3dsp2sp2sp

Hybridisation is given by the following formula: H=V+X−C+A2 Here, V= number of valence electrons in central atom, X= number of monovalent atoms around the central atom, C= positive charge on cation and A= negative charge on anion.

Sulphur trioxide is dissolved in heavy water to form a compound $X$ . The state of hybridisation of sulphur in $X$ is:
$s p^{3}$
$d s p^{2}$
$s p^{2}$
$s p$

Hybridisation is given by the following formula:
$H = \frac{V + X - C + A}{2}$

Here, $V =$ number of valence electrons in central atom, $X =$ number of monovalent atoms around the central atom, $C =$ positive charge on cation and $A =$ negative charge on anion.