Sulphuryl chloride -SO-2Cl-2- reacts with white phosphorus -P-4- to give-OPCl-3- SOCl-2PCl-5- SO-2- S-2Cl-2OPCl-3- SO-2- S-2Cl-2PCl-5- SO-2

Question

Toppr Admin · Accepted Answer

Sulphuryl chloride -SO2Cl2- reacts with white phosphorus -P4- to give phosphorous pentachloride and sulphur dioxide-10SO2Cl2-P4-x2192-4PCl5-10SO2Hence- option A is correct-

Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with white phosphorus $(P_{4})$ to give:
$O P C l_{3}, S O C l_{2}$
$P C l_{5}, S O_{2}, S_{2} C l_{2}$
$O P C l_{3}, S O_{2}, S_{2} C l_{2}$
$P C l_{5}, S O_{2}$

Sulphuryl chloride ( $S O_{2} C l_{2}$ ) reacts with white phosphorus ( $P_{4}$ ) to give phosphorous pentachloride and sulphur dioxide.

$10 S O_{2} C l_{2} + P_{4} \to 4 P C l_{5} + 10 S O_{2}$

Hence, option A is correct.

Sulphuryl chloride (SO2Cl2) reacts with white phosphorus (P4) to give:OPCl3,SOCl2PCl5,SO2,S2Cl2OPCl3,SO2,S2Cl2PCl5,SO2

Sulphuryl chloride (SO2Cl2) reacts with white phosphorus (P4) to give phosphorous pentachloride and sulphur dioxide.10SO2Cl2+P4→4PCl5+10SO2Hence, option A is correct.

Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with white phosphorus $(P_{4})$ to give:
$O P C l_{3}, S O C l_{2}$
$P C l_{5}, S O_{2}, S_{2} C l_{2}$
$O P C l_{3}, S O_{2}, S_{2} C l_{2}$
$P C l_{5}, S O_{2}$

Sulphuryl chloride ( $S O_{2} C l_{2}$ ) reacts with white phosphorus ( $P_{4}$ ) to give phosphorous pentachloride and sulphur dioxide.

$10 S O_{2} C l_{2} + P_{4} \to 4 P C l_{5} + 10 S O_{2}$

Hence, option A is correct.