Sum of 15 consecutive positive integers is a perfect square- The smallest possible value of this is-196169None of these225 144

Question

Toppr Admin · Accepted Answer

Let the 15 positive integers aren-x2212-7-n-x2212-6-n-x2212-5-n-x2212-4-n-x2212-3-n-x2212-2-n-x2212-1-n-n-1-n-2-n-3-n-4-n-5-n-6-n-7Sum is- -n-x2212-7-n-x2212-6-n-x2212-5-n-x2212-4-n-x2212-3-n-x2212-2-n-x2212-1-n-n-1-n-2-n-3-n-4-n-5-n-6-n-7-15nGiven that 15n is a perfect square-x2234- Smallest possible value is-xA0-15-xD7-15-225

Sum of 15 consecutive positive integers is a perfect square. The smallest possible value of this sum is______196169None of these225144

Let the 15 positive integers aren−7,n−6,n−5,n−4,n−3,n−2,n−1,n,n+1,n+2,n+3,n+4,n+5,n+6,n+7Sum is: =n−7+n−6+n−5+n−4+n−3+n−2+n−1+n+n+1+n+2+n+3+n+4+n+5+n+6+n+7=15nGiven that 15n is a perfect square∴ Smallest possible value is 15×15=225

Sum of $15$ consecutive positive integers is a perfect square. The smallest possible value of this sum is______
$196$
$169$
$N o n e o f t h e s e$
$225$
$144$