0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Suppose the wavelength of the incident light in photoelectric effect experiment is increased from 3000Ao to 3040Ao. Find the corresponding change in the stopping potential. [Take the product hc=12.4×107Vm]

Solution
Verified by Toppr

ΔV=ΔEincidente

(hcλ1hcλ2)

=4.1334.078

=5.5×102V

Was this answer helpful?
1
Similar Questions
Q1
Suppose the wavelength of the incident light in photoelectric effect experiment is increased from 3000Ao to 3040Ao. Find the corresponding change in the stopping potential. [Take the product hc=12.4×107Vm]
View Solution
Q2
In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300nm to 400nm. The decrease in the stopping potential is close to: (hce=1240nmV)
View Solution
Q3
In a photoelectric experiment the stopping potential for the incident light of wavelength 4000˚A is 2 volt. If the wavelength be changed to 3000˚A, the stopping potential will be :
View Solution
Q4
In an experiment of photoelectric emission, for incident light of 4000˚A, the stopping potential is 2V. If the wavelength of incident light is made 3000˚A, then stopping potential will be
View Solution
Q5
Wavelength of incident light falling on a photosensitive surface is changed from 2000 oA to 2050 oA. Corresponding change in stopping potential is [Take hc=1240 eVnm] (Write upto two digits after the decimal point.)
View Solution