Supposing the ionization energy of hydrogen atom is 640eV. The shell having energy equal to −40eV is :
n=2
n=3
n=4
n=5
A
n=3
B
n=2
C
n=4
D
n=5
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Solution
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Since EH=−(IE)H×Z2n2
∴Z=1
⇒n=√(IEH)EH=√64040=2×2
∴n=4
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