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Question

Supposing the ionization energy of hydrogen atom is 640 eV. The shell having energy equal to 40 eV is :
  1. n=2
  2. n=3
  3. n=4
  4. n=5

A
n=3
B
n=2
C
n=4
D
n=5
Solution
Verified by Toppr

Since EH=(IE)H×Z2n2

Z=1

n=(IEH)EH=64040=2×2

n=4

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