Take Cupric Chloride -CuCl-2- solution in a beaker- Dip two graphite rod in it- Pass 5V electricity through it-Which gas evolved out through a positive electrode- How did you identify that gas-

Question

Toppr Admin · Accepted Answer

Chloride ions are oxidised by electron loss to form chlorine gas at the positive electrode-Bubbles on surface of electrode indicates chlorine gas-2Cl- -rightarrow Cl-2 -2e-

Take Cupric Chloride $$(CuCl_2)$$ solution in a beaker. Dip two graphite rod in it. Pass $$5V$$ electricity through it.
Which gas evolved out through a positive electrode? How did you identify that gas?

Chloride ions are oxidised by electron loss to form chlorine gas at the positive electrode.

Bubbles on surface of electrode indicates chlorine gas.

$$2Cl^- \rightarrow Cl_2 +2e^-$$

Take Cupric Chloride $$(CuCl_2)$$ solution in a beaker. Dip two graphite rod in it. Pass $$5V$$ electricity through it.Which gas evolved out through a positive electrode? How did you identify that gas?

Chloride ions are oxidised by electron loss to form chlorine gas at the positive electrode.Bubbles on surface of electrode indicates chlorine gas.$$2Cl^- \rightarrow Cl_2 +2e^-$$

Take Cupric Chloride $$(CuCl_2)$$ solution in a beaker. Dip two graphite rod in it. Pass $$5V$$ electricity through it.
Which gas evolved out through a positive electrode? How did you identify that gas?

Chloride ions are oxidised by electron loss to form chlorine gas at the positive electrode.

Bubbles on surface of electrode indicates chlorine gas.

$$2Cl^- \rightarrow Cl_2 +2e^-$$