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Standard VII
Mathematics
Question
tan
2
θ
+
cot
2
θ
=
2
. Then
θ
=
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Solution
Verified by Toppr
tan
2
θ
+
(
1
/
tan
2
θ
)
−
2
=
0
or
tan
4
θ
−
2
tan
2
θ
+
1
=
0
∴
(
tan
2
θ
−
1
)
2
=
0
∴
tan
2
θ
=
1
or
tan
θ
=
±
1
=
±
tan
(
π
/
4
)
∴
θ
=
n
π
±
π
/
4
.
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