Temperature of an iron block is displaystyle - 140 - o -F- Its temperature in celcius scale will bedisplaystyle - 100 - o -Cdisplaystyle - 32 - o -Cdisplaystyle - 60 - o -Cdisplaystyle - 140 - o -C

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Toppr Admin · Accepted Answer

Temperature of an iron block is 140oF- The formula to be used is -F-x2212-32-xD7-59-C-Substitute values in the above equation-140oF-x2212-32-xD7-59-60oC-Thus- the temperature of the iron block in celsius scale will be 60oC-

Temperature of an iron block is $140^{o} F$ . Its temperature in celcius scale will be
$100^{o} C$
$32^{o} C$
$60^{o} C$
$140^{o} C$

Temperature of an iron block is $140^{o} F$ .
The formula to be used is $(F - 32) \times \frac{5}{9} = C$ .
Substitute values in the above equation.
$(140^{o} F - 32) \times \frac{5}{9} = 60^{o} C$ .
Thus, the temperature of the iron block in celsius scale will be $60^{o} C$ .

Temperature of an iron block is 140oF. Its temperature in celcius scale will be100oC32oC60oC140oC

Temperature of an iron block is 140oF. The formula to be used is (F−32)×59=C.Substitute values in the above equation.(140oF−32)×59=60oC.Thus, the temperature of the iron block in celsius scale will be 60oC.

Temperature of an iron block is $140^{o} F$ . Its temperature in celcius scale will be
$100^{o} C$
$32^{o} C$
$60^{o} C$
$140^{o} C$

Temperature of an iron block is $140^{o} F$ .
The formula to be used is $(F - 32) \times \frac{5}{9} = C$ .
Substitute values in the above equation.
$(140^{o} F - 32) \times \frac{5}{9} = 60^{o} C$ .
Thus, the temperature of the iron block in celsius scale will be $60^{o} C$ .