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Hardness of Water and Treatment

Question

Temporary hardness of water is removed in Clark's process by adding :
caustic soda
calgon
lime
borax

A

calgon

B

borax

C

caustic soda

D

lime

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Solution

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Temporary hardness of water is removed in Clark's process by adding lime.

$C a (H C O_{3})_{2} + C a (O H)_{2} \to 2 C a C O_{3} ↓ + 2 H_{2} O$

Temporary hardness of water is due to the presence of bicarbonates of magnesium and calcium. They react with calcium hydroxide to form carbonates of magnesium and calcium. Thus, the temporary hardness of water is removed.

So, the correct option is $D$

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