The acceleration due to gravity on the surface of a planet whose mass is same as that of the Earth and radius is half of that of the Earth is: (Mass of Earth: 6×1024kg and Radius of Earth: 6.4×103km)
35.08m/s2
39.08m/s2
28.08m/s2
9.08m/s2
None of these
A
9.08m/s2
B
35.08m/s2
C
28.08m/s2
D
None of these
E
39.08m/s2
Open in App
Solution
Verified by Toppr
Was this answer helpful?
9
Similar Questions
Q1
The acceleration due to gravity on the surface of a planet whose mass is same as that of the Earth and radius is half of that of the Earth is: (Mass of Earth: 6×1024kg and Radius of Earth: 6.4×103km)
View Solution
Q2
The mass of a planet is double and its radius is half compared to that of earth. Assuming g=10m/s2 on earth, the acceleration due to gravity at the planet will be :
View Solution
Q3
At what height above the surface of earth acceleration due to gravity becomes 1mm/s2? [Take R as radius of earth and acceleration due to gravity at the surface of earth g=10m/s2]
View Solution
Q4
If the acceleration due to gravity on the surface of the earth is 9.8m/s2, what will be the acceleration due to gravity on the surface of a planet whose mass and radius both are two times the corresponding quantities for the earth ?
View Solution
Q5
Given mass of earth is 6 × 1024 kg and mean radius of earth is 6.4 × 106 m. Calculate the value of acceleration due to gravity (g) on the surface of the earth.