The activity of a nuclide is 15millicurie- If its decay constant is 0-005 sec-1- the number of atoms present in it is

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Decay constant -0-005sec-x2212-1-x3BB-Activity of nuclei -15-xD7-3-7-xD7-107dps-x2235-1millicurie-3-7-xD7-107dps-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-5-55-xD7-108dps

The activity of a nuclide is $15$ millicurie. If its decay constant is $0.005$ sec $^{- 1}$ , the number of atoms present in it is

Decay constant $= 0.005 s e c^{- 1} = λ$
Activity of nuclei $= 15 \times 3.7 \times 10^{7} d p s [∵ 1 m i l l i c u r i e = 3.7 \times 10^{7} d p s]$
$= 5.55 \times 10^{8} d p s$

The activity of a nuclide is 15millicurie. If its decay constant is 0.005 sec−1, the number of atoms present in it is

Decay constant =0.005sec−1=λActivity of nuclei =15×3.7×107dps[∵1millicurie=3.7×107dps] =5.55×108dps

The activity of a nuclide is $15$ millicurie. If its decay constant is $0.005$ sec $^{- 1}$ , the number of atoms present in it is

Decay constant $= 0.005 s e c^{- 1} = λ$
Activity of nuclei $= 15 \times 3.7 \times 10^{7} d p s [∵ 1 m i l l i c u r i e = 3.7 \times 10^{7} d p s]$
$= 5.55 \times 10^{8} d p s$