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# The activity of a radioactive substance is R1 at time t1 and R2 at time t2 where t2>t1.Its decay constant is λ.Then the number of atoms decayed between the time interval t1 and t2 areln(2)λ(R1R2)R1e−λt2−R2e−λt2(R1−R2λ)λ(R1−R2)

A
ln(2)λ(R1R2)
B
λ(R1R2)
C
R1eλt2R2eλt2
D
(R1R2λ)
Solution
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#### b'Let N1 be the number of atoms at t1∴R1=λN1Let N2 be the number of atoms at t2∴R2=λN2⇒R1−R2=λN1−λN2⇒N1−N2=R1−R2λ∴ number of atoms decayed between the time interval t1 and t2 are R1−R2λ'

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