The adjoining figure- shows two straight lines AB and CD intersecting P- If angle BPC - 4x - 5-circ and angle APD - 3x - 15-circ- the value of x-

Question

Toppr Admin · Accepted Answer

By referring given figure-The value of -x- is calculated as-3x - 15-circ - 4x - 5-circ- -By vertically opposite angles-3x - 4x - -5-circ - 15-circ-x - -20-circ-x - 20-circ-

The adjoining figure, shows two straight lines AB and CD intersecting at P. If $$\angle BPC = 4x - 5^\circ$$ and $$\angle APD = 3x + 15^\circ,$$ find the value of $$x$$.

By referring given figure,
The value of $$x$$ is calculated as,
$$3x + 15^\circ = 4x - 5^\circ$$ (By vertically opposite angles)
$$3x - 4x = -5^\circ - 15^\circ$$
$$-x = -20^\circ$$
$$x = 20^\circ$$

The adjoining figure, shows two straight lines AB and CD intersecting at P. If $$\angle BPC = 4x - 5^\circ$$ and $$\angle APD = 3x + 15^\circ,$$ find the value of $$x$$.

By referring given figure,The value of $$x$$ is calculated as,$$3x + 15^\circ = 4x - 5^\circ$$ (By vertically opposite angles)$$3x - 4x = -5^\circ - 15^\circ$$$$-x = -20^\circ$$$$x = 20^\circ$$

By referring given figure,
The value of $$x$$ is calculated as,
$$3x + 15^\circ = 4x - 5^\circ$$ (By vertically opposite angles)
$$3x - 4x = -5^\circ - 15^\circ$$
$$-x = -20^\circ$$
$$x = 20^\circ$$