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Standard XII
Chemistry
Chlorination
Question

The alternative reaction pathways for radical chain reactions of Br2 with ethane may be represented as follows.
1} CH3CH3+Br2→CH3CH2Br+HBr
2) CH3CH3+Br2→2CH3Br
Which statement is correct?

  1. Reaction (1) is more likely because it is more endothermic
  2. Reaction (2) is more likely because it is more endothermic
  3. Reaction (1) is more likely because it is more exothermic
  4. Reaction (2) is more likely because it is more exothermic

A
Reaction (2) is more likely because it is more exothermic
B
Reaction (1) is more likely because it is more exothermic
C
Reaction (1) is more likely because it is more endothermic
D
Reaction (2) is more likely because it is more endothermic
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Solution
Verified by Toppr

Halogenation is supposed to proceed via free radical chain mechanism.
CH3CH3+Br2→CH3CH2Br+HBr
CH3CH3+Br2→2CH3Br
In the first reaction, more energy released than in the second reaction. So the first reaction is more likely as enthalpy is more negative in the first reaction than the second reaction.
More the negative enthalpy, more negative free energy, greater the spontaneity.

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Which statement is correct?

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