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Question

The amplitude of a particle performing S.H.M. is A. The displacement at which its velocity will be half of the maximum velocity is
  1. A/2
  2. A/3
  3. 3A/2
  4. 2A/3

A
A/2
B
2A/3
C
3A/2
D
A/3
Solution
Verified by Toppr

x=Asinωt
V=dxdt=Aωcosωt
Vmax=Aω
V=Vmax2=Aωcosωt
Aω2=Aωcosωt
cosωt=12
ωt=600
x=Asinωt
=Asin600
=A32
so, amplitude is 3A2

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