The amplitude of electric field in a parallel light beam of intensity $4 W m^{- 2}$ is
$35.5 N C^{- 1}$
$45.5 N C^{- 1}$
$49.5 N C^{- 1}$
$55.5 N C^{- 1}$

Question

The amplitude of electric field in a parallel light beam of intensity 4W-m-2- is35-5N-C-1-45-5N-C-1-49-5N-C-1-55-5N-C-1-

Toppr Admin · Accepted Answer

Intensity - -xA0- I-12c-x3F5-oE2 -xA0- where c and E are the speed of light and amplitude of electric field respectively-4-12-xD7-3-xD7-108-xD7-8-85-xD7-10-x2212-12-xD7-E-2-x27F9-E-55-5NC-x2212-1

The amplitude of electric field in a parallel light beam of intensity 4Wm−2 is35.5NC−145.5NC−149.5NC−155.5NC−1

Intensity , I=12cϵoE2 where c and E are the speed of light and amplitude of electric field respectively.4=12×3×108×8.85×10−12×|E|2⟹|E|=55.5NC−1

The amplitude of electric field in a parallel light beam of intensity $4 W m^{- 2}$ is
$35.5 N C^{- 1}$
$45.5 N C^{- 1}$
$49.5 N C^{- 1}$
$55.5 N C^{- 1}$

Intensity , $I = \frac{1}{2} c ϵ_{o} E^{2}$ where $c$ and $E$ are the speed of light and amplitude of electric field respectively.
$4 = \frac{1}{2} \times 3 \times 10^{8} \times 8.85 \times 10^{- 12} \times | E |^{2}$
$⟹ | E | = 55.5 N C^{- 1}$