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Question

The amplitude of electric field in a parallel light beam of intensity 4Wm2 is
  1. 35.5NC1
  2. 45.5NC1
  3. 49.5NC1
  4. 55.5NC1

A
45.5NC1
B
55.5NC1
C
35.5NC1
D
49.5NC1
Solution
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Intensity , I=12cϵoE2 where c and E are the speed of light and amplitude of electric field respectively.
4=12×3×108×8.85×1012×|E|2
|E|=55.5NC1

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