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Question

The angle of a prism is 60∘. If the refractive index of the material of the prism is √2 the angle of minimum deviation is :45∘60∘30∘sin−1(23)

A
45
B
60
C
sin1(23)
D
30
Solution
Verified by Toppr

μ=sin(D+A2)sin(A/2) μ=2sin(D+602) =2sin(D+602) 1√2=sinD+60∘2 45∘=D+60∘2 D=(90−60)∘ =30∘

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