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>> $The angle of a prism is 60 ^\circ . If the r$

Question

The angle of a prism is 60 $^{\circ}$ . If the refractive index of the material of the prism is $2$ the angle of minimum deviation is :

A

45 $^{\circ}$

B

60 $^{\circ}$

C

30 $^{\circ}$

D

sin $^{- 1} (\frac{2}{3})$

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Updated on : 2022-09-05

Solution

Verified by Toppr

Correct option is C)

$μ = \frac{s i n ( \frac{D + A}{2} )}{s i n ( A / 2 )}$

$μ = 2 s i n (\frac{D + 6 0}{2})$

$= 2 s i n (\frac{D + 6 0}{2})$

$\frac{1}{2} = s i n \frac{D + 6 0 ^{\circ}}{2}$

$4 5^{\circ} = \frac{D + 6 0 ^{\circ}}{2}$

$D = (90 - 60)^{\circ}$

$= 3 0^{\circ}$

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