The angle of elevation the of a tower from a point 10 m from the foot of the tower is displaystyle 30-circ- The height of the tower is displaystyle 10 sqrt-3- displaystyle 10- sqrt-3- displaystyle 10 sqrt-3-3 10

Question

The angle of elevation the of a tower from a point 10 m from the foot of the tower is displaystyle 30-circ-  The height of the tower is displaystyle 10 sqrt-3- displaystyle 10- sqrt-3- displaystyle 10 sqrt-3-3 10

Toppr Admin · Accepted Answer

Tan30-x2218-h10-1-x221A-3-h10or h-10-x221A-3

The angle of elevation at the top of a tower from a point 10 m from the foot of the tower is $30^{\circ}$ The height of the tower is
$10 \sqrt{3}$
$10 / \sqrt{3}$
$10 \sqrt{3} / 3$
10

$tan 30^{\circ} = \frac{h}{10} = \frac{1}{\sqrt{3}} = \frac{h}{10}$
$o r$ $h = \frac{10}{\sqrt{3}}$

The angle of elevation at the top of a tower from a point 10 m from the foot of the tower is 30∘ The height of the tower is 10√310/√310√3/310

tan30∘=h10=1√3=h10or h=10√3

The angle of elevation at the top of a tower from a point 10 m from the foot of the tower is $30^{\circ}$ The height of the tower is
$10 \sqrt{3}$
$10 / \sqrt{3}$
$10 \sqrt{3} / 3$
10

$tan 30^{\circ} = \frac{h}{10} = \frac{1}{\sqrt{3}} = \frac{h}{10}$
$o r$ $h = \frac{10}{\sqrt{3}}$