The angle which exceeds its complement by $20^{\circ}$ is:
$45^{\circ}$
$55^{\circ}$
$70^{\circ}$
$110^{\circ}$

Question

The angle which exceeds its complement by 20-circ- is-45-circ-55-circ-70-circ-110-circ-

Toppr Admin · Accepted Answer

Let the required angle be x-We knows- complementary angles - Sum of two angles is 90o-x2234-x-90o-x2212-x-20o-x2234- x-90o-x2212-x-20o-x2234-xA0-2x-110o-x2234-x-55o-Hence- option B is correct-

The angle which exceeds its complement by 20∘ is:45∘55∘70∘110∘

Let the required angle be x.We knows, complementary angles = Sum of two angles is 90o.∴x=(90o−x)+20o∴ x=90o−x+20o∴2x=110o∴x=55o.Hence, option B is correct.

The angle which exceeds its complement by $20^{\circ}$ is:
$45^{\circ}$
$55^{\circ}$
$70^{\circ}$
$110^{\circ}$

Let the required angle be $x$ .
We knows, complementary angles $=$ Sum of two angles is $90^{o}$ .
$∴ x = (90^{o} - x) + 20^{o}$
$∴$ $x = 90^{o} - x + 20^{o}$
$∴$ $2 x = 110^{o}$
$∴ x = 55^{o}$ .
Hence, option $B$ is correct.