The angles $$x-10^o$$ and $$190^o-x$$ are
A
interior angles on the same side of the transversal
Correct option is D. supplementary
Option (d) is correct.
Given that $$x-10^o+190^o-x$$
$$\Rightarrow 190^o -10^o$$
$$\Rightarrow180^o$$
Therefore, given angles are supplementary.